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NEW QUESTION: 1
Which of the following is a continuity plan test that uses actual resources to simulate a system crash to cost-effectively obtain evidence about the plan's effectiveness?
A. Post test
B. Paper test
C. Preparedness test
D. Walkthrough
Answer: C
Explanation:
Explanation/Reference:
Explanation:
A preparedness test is a localized version of a full test, wherein resources are expended in the simulation of a system crash. This test is performed regularly on different aspects of the plan and can be a cost- effective way to gradually obtain evidence about the plan's effectiveness. It also provides a means to improve the plan in increments. A paper test is a walkthrough of the plan, involving major players, who attempt to determine what might happen in a particular type of service disruption in the plan's execution. A paper test usually precedes the preparedness test. A post-test is actually a test phase and is comprised of a group of activities, such as returning all resources to their proper place, disconnecting equipment, returning personnel and deleting all company data from third-party systems. A walkthrough is a test involving a simulated disaster situation that tests the preparedness and understanding of management and staff, rather than the actual resources.

NEW QUESTION: 2
회사에서 다양한 유형의 Amazon EC2 온 디맨드 인스턴스를 사용하고 있습니다. 회사는 이러한 인스턴스가 워크로드에 필요한 것보다 더 큰 CPU 및 메모리 용량을 가지고 있다고 의심합니다. 회사는 비용 최적화를위한 권장 사항을 얻기 위해 어떤 조치를 취해야합니까? (2 개 선택)
A. Cost Explorer 적정 크기 권장 사항 사용
B. Amazon Inspector를 사용하여 활용도가 낮은 EC2 인스턴스를 식별합니다.
C. 인스턴스 유형 권장 사항에 AWS 예산 사용
D. 인스턴스 유형 권장 사항에 AWS Compute Optimizer 사용
E. 인스턴스 유형 권장 사항에 AWS Trusted Advisor 사용
Answer: A,E

NEW QUESTION: 3

public class Emp
private String eName;
private Integer eAge;
Emp(String eN, Integer eA) {
this.eName = eN;
this.eAge = eA;
}
public Integer getEAge () {return eAge;}
public String getEName () {return eName;}
}
and code fragment:
List<Emp>li = Arrays.asList(new Emp("Sam", 20), New Emp("John", 60), New Emp("Jim",
51));
Predicate<Emp> agVal = s -> s.getEAge() > 50;//line n1
li = li.stream().filter(agVal).collect(Collectors.toList());
Stream<String> names = li.stream()map.(Emp::getEName);//line n2
names.forEach(n -> System.out.print(n + " "));

A. Option A
B. Option D
C. Option B
D. Option C
Answer: A

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