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NEW QUESTION: 1
You need to display the first names of all customers from the customers table that contain the character 'e' and have the character 'a' in the second last position.
Which query would give the required output?

A. Option A
B. Option C
C. Option D
D. Option B
Answer: A
Explanation:
The SUBSTR(string, start position, number of characters) function accepts three parameters and returns a string consisting of the number of characters extracted from the source string, beginning at the specified start position:
substr('http://www.domain.com', 12, 6) = domain
The position at which the first character of the returned string begins.
When position is 0 (zero), then it is treated as 1.
When position is positive, then the function counts from the beginning of string to find the first
character.
When position is negative, then the function counts backward from the end of string.
substring_length
The length of the returned string. SUBSTR calculates lengths using characters as defined by the
input character set. SUBSTRB uses bytes instead of characters. SUBSTRC uses Unicode
complete characters.
SUBSTR2 uses UCS2 code points. SUBSTR4 uses UCS4 code points.
When you do not specify a value for this argument, then the function
The INSTR(source string, search item, [start position], [nth occurrence of search item]) function returns a number that represents the position in the source string, beginning from the given start position, where the nth occurrence of the search item begins:
instr('http://www.domain.com', '.', 1, 2) = 18

NEW QUESTION: 2
With which protocol is CoAP designed to be used?
A. SNMP
B. TCP
C. UDP
D. XMPP
Answer: C

NEW QUESTION: 3
The following debug messages are noticed for HSRP group 2. But still neither R1 nor R2 has identified one of them as standby router. Identify the reason causing the issue.
Note: only show commands can be used to troubleshoot the ticket.



A. There is an HSRP group number mismatch
B. HSRP group priority misconfiguration
C. There is an HSRP authentication misconfiguration
D. The ACL applied to interface is blocking HSRP hello packet exchange
E. This is not an HSRP issue: this is DHCP issue.
Answer: D
Explanation:
Explanation/Reference:
Check the link between R1 & R2 where HSRP group 2 is running (interface E1/0)

As we see R1 is using access-list 102 to filter traffic coming to interface E1/0 (inbound direction). Continue checking the access-list 102 of R1:

R1 is blocking any traffic send to 224.0.0.102. Notice that in the syntax of an access-list, the source address is always defined before the destination address. "224.0.0.102" is the muticast address which HSRP version 2 uses to send Hello packets to (instead of 224.0.0.2 of HSRP version 1). Therefore all HSRP sent from neighbor (R2 in this case) to R1 is dropped. R1 keeps sending HSRP Hello packets and think it is the active HSRP router.

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